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5y+5=12y^2-12y
We move all terms to the left:
5y+5-(12y^2-12y)=0
We get rid of parentheses
-12y^2+5y+12y+5=0
We add all the numbers together, and all the variables
-12y^2+17y+5=0
a = -12; b = 17; c = +5;
Δ = b2-4ac
Δ = 172-4·(-12)·5
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-23}{2*-12}=\frac{-40}{-24} =1+2/3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+23}{2*-12}=\frac{6}{-24} =-1/4 $
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